rrb group d previous year question paper mathematic section telugu and english Wisdom helps

RRB Group D Previous Year Mathematics Solved Paper with Shortcuts | Wisdom Helps
RRB Group D Exam Prep

RRB Group D Mathematics Previous Year Question Paper Solved with Shortcuts

By Mahesh Sir (Wisdom Helps) | Practice Guide & Comprehensive Solutions

Welcome aspirants! If you are preparing for upcoming railway examinations like RRB Group D, RRB NTPC, or RRB ALP, mastering the Mathematics section is critical for scoring top percentile ranks. In this article, we break down real exam questions from the previous year paper with step-by-step traditional methods alongside Wisdom Helps short tricks to help you solve questions in under 15 seconds.

📌 Essential Mathematics Formulas & Shortcuts

Review these important formulas frequently tested in competitive railway exams:

Topic Standard Formula / Speed Trick
Average Total Sum = n × Average
Average Speed Avg Speed = 2xy / (x + y) (When distance is constant)
LCM & HCF LCM × HCF = Product of Two Numbers (N1 × N2)
Effective CI (2 Years) Effective Rate = x + y + (x × y) / 100 %
Discount % (Buy X Get Y) Discount % = [Free Quantity / Total Quantity] × 100

📝 Solved Questions with Step-by-Step Solutions

Q1 Average Age Calculation

Question: The average age of 26 students in a class is 26 years. If the age of the teacher is included, the average age of the entire group becomes 27 years. What is the age of the teacher (in years)?

Standard Method:

Sum of ages of 26 students = 26 × 26 = 676 years
Sum of ages including teacher (27 people) = 27 × 27 = 729 years
Teacher's Age = 729 − 676 = 53 years

Wisdom Helps Shortcut:

New Average = 27
Increase for existing 26 students = 26 × 1 = 26
Teacher's Age = 27 + 26 = 53 Years

Q2 Percentage Application

Question: If 20% of a number is added to 90, the result is the same number. Find 80% of that same number.

Solution:

Let the number be x.
20% of x = (1/5)x
Given: (1/5)x + 90 = x ⇒ x − (1/5)x = 90 ⇒ (4/5)x = 90
x = (90 × 5) / 4 = 112.5
Now, 80% of the number = 112.5 × (80 / 100) = 90

Q3 Average Speed (Time & Distance)

Question: Smriti travels to a shopping mall at a speed of 21 km/h and returns along the same route at a speed of 69 km/h. Find her average speed for the whole journey.

Solution:

Since distance is constant, apply the harmonic average speed formula:
Average Speed = 2xy / (x + y)
= (2 × 21 × 69) / (21 + 69) = 2898 / 90 = 32.2 km/h

Q4 Profit & Loss with Markup

Question: An article was bought for ₹8,900. It was marked up by 40% above the cost price and then sold at a discount of 5% on the marked price. What was the profit percentage on the transaction?

Wisdom Helps Zero-Calculation Trick:

Ignore the actual cost value ₹8,900 as percentage profit is requested!
Let Cost Price (CP) = 100%
Marked Price (MP) = 140%
Discount = 5% of 140 = 7%
Selling Price (SP) = 140 − 7 = 133%
Profit Percentage = 133% − 100% = 33%

Q5 Ratio Simplification

Question: Which of the following ratios is equivalent to 3 : 2?

Divisibility Trick:

Check option 54 : 36.
Divide both terms by 18: 54/18 = 3 and 36/18 = 2.
Ratio = 3 : 2

Q6 Trigonometry & Pythagorean Triplets

Question: If tan θ = 12 / 5, find the value of sec θ.

Solution:

tan θ = Opposite / Adjacent = 12 / 5
Using Pythagorean Triplet (5, 12, 13), Hypotenuse = 13.
sec θ = Hypotenuse / Adjacent = 13 / 5

Q7 Mensuration (Cylinder Surface Area)

Question: The Total Surface Area (TSA) of a solid right circular cylinder is 542. If its Curved Surface Area (CSA) is 2/5 of its TSA, find its CSA.

Fast Decimal Calculation Trick:

CSA = (2 / 5) × 542
Multiply numerator and denominator by 2 to make the denominator 10:
CSA = (4 × 542) / 10 = 2168 / 10 = 216.8

Q8 HCF & LCM Properties

Question: Two numbers have an HCF of 18 and an LCM of 1512. If one of the numbers is 126, find the positive difference between the two numbers.

Solution:

Formula: HCF × LCM = Number1 × Number2
18 × 1512 = 126 × Number2
Number2 = (18 × 1512) / 126 = 216
Difference = 216 − 126 = 90

Q9 Promotional Discount Rates

Question: A scheme offers "Buy 6, Get 4 Free". What is the effective discount percentage?

Solution:

Discount % = [Free Articles / Total Articles] × 100
Total Articles = 6 + 4 = 10
Discount % = (4 / 10) × 100 = 40%

Q10 Compound Interest

Question: What will be the total amount on a principal sum of ₹6,800 at 15% per annum compounded annually for 2 years?

Effective Interest Rate Method:

Effective Compound Interest Rate for 2 years = 15 + 15 + (15 × 15)/100 = 32.25%
Total Amount Rate = 100% + 32.25% = 132.25%
Total Amount = 6800 × (132.25 / 100) = 68 × 132.25 = 8993
(Tip: Use Digit Sum matching in exams to verify choices instantly!)

💡 Key Exam Tips for RRB Mathematics Section

  • Focus on Speed & Accuracy: Practice solving questions using shortcuts like Effective Percentages, Digit Sum, and Triplet Recognition to save critical exam time.
  • Memorize Basic Squares & Cubes: Learn squares up to 30 and cubes up to 15 to perform fast Mental Math.
  • Analyze PYQs: Previous Year Questions give you direct insight into the exam pattern and question weightage for topics like Arithmetic, Algebra, and Mensuration.

Join the Wisdom Helps Community

Get daily PDF notes, practice sets, and mock tests directly on our social channels:

Post a Comment

Previous Post Next Post